10x^2-19x-50=6

Solution for 10x^2-19x-50=6 equation:

10x^2-19x-50=6

We move all terms to the left:

10x^2-19x-50-(6)=0

We add all the numbers together, and all the variables

10x^2-19x-56=0

a = 10; b = -19; c = -56;
Δ = b2-4ac
Δ = -192-4·10·(-56)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-51}{2*10}=\frac{-32}{20}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+51}{2*10}=\frac{70}{20}
=3+1/2
$